(−1)5 − (−2)4\left(-1\right)^5\:-\:\left(-2\right)^4(−1)5−(−2)4
limx→−2(x3+3x2+3xx+2)\lim_{x\to-2}\left(\frac{x^3+3x^2+3x}{x+2}\right)x→−2lim(x+2x3+3x2+3x)
−1+2+2-1+2+2−1+2+2
dydx(−10x+9x2)\frac{dy}{dx}\left(-10x+9x^2\right)dxdy(−10x+9x2)
(10a+4b)(10a−6b)\left(10a+4b\right)\left(10a-6b\right)(10a+4b)(10a−6b)
6−5x=x6-\frac{5}{x}=x6−x5=x
dxdy=−13x3\frac{dx}{dy}=-\frac{1}{3}x^3dydx=−31x3
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