$3x^2+x-4$
$\lim_{x\to1}\left(x^{2+3x}\right)$
$xsinydx=-\left(x^2+1\right)cosydy$
$x^2-5x+2=0$
$-x^2+10x-9$
$\frac{5x-6}{2}>x+2$
$\frac{8x^2+16x-6}{2x+3}$
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