$\int_{-3}^5-xdx$
$x^2-6x+8>-5x+x^2$
$\frac{dy}{dx}=\frac{1}{xy+x+y-1}$
$3\cdot5\cdot6$
$\frac{dy}{dx}=\frac{4\left(3x+y-2\right)}{3x+y}$
$\frac{2x^2-3x+4}{x-5}$
$\int\left(\sqrt{2+5y}\right)dy$
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