$x^2y+2xy=3x^2$

$\left(f^2+z\right)\left(3f^2+4z\right)$

$\left(\frac{\left(300\right)\left(106.55\right)^3}{3}\right)+\left(6.26-1\right)\cdot227\cdot\left(106.55-40\right)^2+\left(6.26\right)\cdot\left(628\right)\left(\left(560-106.55\right)^2\right)$

$7z-3=4$

$x^4\cdot e^{\left(-x\right)^2}$

$\ln\left(x-3\right)=\ln\left(7x-23\right)-\ln\left(x+1\right)$

$-\frac{1}{4}a^{n-2}+\frac{1}{2}a^{n-2}$