$x^2+4x+4=12$
$-12\left(2\right)+8\left(4\right)+3$
$\left(14\:x+y\right)\left(14\:x-y\right)$
$x^2-2=8x$
$log2\left(4x\right)\:-\:log2\left(3\right)=4$
$2x^2-13x+15$
$64x^3-125y^3$
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