$y+6=0$
$5+4+1$
$\frac{dy}{dx}+3\:y=2.\cos\left(3x\right)$
$3x^2-9x=-27$
$\:\frac{1}{\sqrt{1-x}}$
$a^2-43a+432$
$\left(2x^2-5x+6\right)\left(2x^4-5x^3-6x^2+4x-3\right)$
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