$\frac{1}{3}x\:+\:4;\:x=12$

$\lim_{x\to1}\left(\frac{x-1-\ln\left(x\right)}{\ln\left(x\right)x-1}\right)$

$\left(2m^3n+8\right)^2$

$\lim_{x\to0}\left(\ln\left(x^3\cdot e^{-3x}\right)\right)$

$-7.322+5.37$

$\frac{dy}{dx}\:-\frac{y}{x}=\frac{x}{3y}$

$2cos\left(\frac{3.1416}{3}\right)$