$\left(3x^2-2x+5\right)-00$
$\left(-31\right)-\left(14\right)-\left(-8\right)$
$x^{10}-25$
$-21x+24=-56x-46$
$2a^5b^4c-3a^4b^3c^2+\frac{1}{3}a^3b^2c^3$
$4x^3+24x^2+12x+40$
$\frac{dy}{dt}=\frac{t^4}{5y^2}$
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