$\frac{\pi}{7}=\frac{x}{4}$
$8\cdot\left(2+9-1-4-7\right)$
$\int3\left(3x-7\right)^4dx$
$\ln\left(\sqrt{\frac{\left(2x-3\right)}{2x+1}}\right)$
$\left(5+a\right)\left(5-b\right)$
$\lim_{x\to0}\left(ln\left|x\right|-ln\left|x\right|\right)$
$10x+8=8x+16$
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