$1+7\cdot5+5$
$x^2-22x+64$
$16y^2-2y-3=0$
$72x^2+5x-3$
$\frac{\left(4h^5\right)^2}{20h^8}$
$2x^2-2x-40$
$\lim_{x\to0}\left(\frac{ax+bx}{ax\ln\left(bx\right)}\right)$
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