$\int\frac{\left(x-1\right)}{x\left(x^2+1\right)}dx$

$\frac{d}{dx}\sin\left(\arccos\left(4x\right)\right)$

$\frac{dy}{dx}\left(x^2y=8\right)$

$\left(x+20\right)\left(x+20\right)$

$2x-7=1$

$\frac{u^{\frac{3}{2}}}{\frac{3}{2}}$

$\frac{\tan\:47^{\circ}\:-\tan\:\left(-13^{\circ}\:\right)}{1+\tan\:47^{\circ}\:\tan\:\left(-13^{\circ}\:\right)}$