Exercise
$\frac{x^2}{1-5x}$
Step-by-step Solution
$\begin{array}{l}\phantom{-5x\phantom{;}+1;}{\frac{1}{-5}x\phantom{;}+\frac{0.2}{-5}\phantom{;}\phantom{;}}\\-5x\phantom{;}+1\overline{\smash{)}\phantom{;}x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-5x\phantom{;}+1;}\underline{-x^{2}+0.2x\phantom{;}\phantom{-;x^n}}\\\phantom{-x^{2}+0.2x\phantom{;};}\phantom{;}0.2x\phantom{;}\phantom{-;x^n}\\\phantom{-5x\phantom{;}+1-;x^n;}\underline{-0.2x\phantom{;}+0.04\phantom{;}\phantom{;}}\\\phantom{;-0.2x\phantom{;}+0.04\phantom{;}\phantom{;}-;x^n;}\phantom{;}0.04\phantom{;}\phantom{;}\\\end{array}$
$\frac{1}{-5}x+\frac{0.2}{-5}+\frac{0.04}{1-5x}$
Final answer to the exercise
$\frac{1}{-5}x+\frac{0.2}{-5}+\frac{0.04}{1-5x}$