$\frac{-18d^2-6d}{3d}$
$-4y^2+11y^2$
$\int_{-\infty\:}^0\:xe^{4x^2-1}dx$
$3x+2\le\:2x+3$
$\frac{16x^4-8x^2+12x}{4x^2}$
$-19\cdot4$
$\lim_{x\to1}\left(x\left(\frac{1}{1-x}\right)\right)$
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