$\left(1+3x^2+3x^4+x^6\right)\left(1+v^2x^2\right)$

$\int\frac{8}{x\left(x+2\right)\left(x-2\right)}dx$

$\left(\frac{x^2}{4}\right)\cdot2$

$\left(4x^3-2yz^3\right)^2$

$\int\left(-x-8\right)^9dx$

$\frac{1}{4}x\:+4\ge6\left(1-\frac{2}{7}x\right)$

$\left(4x^{-3}\right)^4$