$\left(4x-10\right)\left(2x+3\right)$
$cos^2x=\left(1+sinx\right)\left(1+sin\left(-x\right)\right)$
$12\left(\frac{600}{1}\right)\left(480\right)$
$\frac{x^3+27}{3+x}$
$x\:+\:x\:-\:x\:$
$\frac{3}{4}\left(8y-12\right)$
$x\:=\:2x\:+\:8$
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