$\left(-2-3t\right)\left(-7+5t\right)$
$\lim_{x\to\infty}\left(\frac{1+e^{-11x}}{9+x^2}\right)$
$10\left(3-2\right)$
$\frac{4a^2b^5}{-2ab}$
$\lim_{x\to0}\left(1-1x\right)$
$\frac{\left(25-c^2\right)}{\left(5-c\right)}$
$\frac{1}{6}\left(-10x-4\right)$
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