$\frac{27}{7},\pi,\sqrt{14}\sqrt{16},27.4,\:\frac{65}{13}$
$5x>15$
$\frac{\left(x+2\right)}{\left(x^2-3x+2\right)}$
$\frac{x+6}{x}$
$-5-7+14+1\:$
$\left(\frac{2}{x}\right)^4$
$x^2+32=12x$
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