$\lim_{x\to0}\left(\frac{\ln\left(^2\right)}{x^7-1}\right)$
$\frac{x^2-4x-5}{x}$
$\frac{a+3}{a}+\frac{3a-3}{3a}$
$\frac{1}{\sqrt{\left(x^2+1\right)}-1}\:$
$\frac{3x+1}{2x-3}\ge2$
$3x^3-y+5x=x^2$
$4+4x\sqrt{1}+4x^{2}$
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