$\frac{x^3+3}{x-1}$
$2x^2-8x-3x+52$
$\left(-3\right)-\left(-2\right)\left(+3\right)\:+\left(-8\right)\left(+3\right)$
$\left(x\:+\:y\:-\:x\right)\left(x\:-\:y\:+\:x\right)$
$7.95+17.4j=-11.52+17.4j$
$-x^2+14x+57$
$0.75\:\:\frac{3}{5}$
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