$\left(x+\frac{1}{4}\right)\left(x+\frac{1}{3}\right)$
$sen^4x\:+\:sen^2x\:=0$
$\left(1-4+2\right)\left(-9\right)$
$\left(y+2\right)\left(y-1\right)$
$f\left(x\right)=\left(x^2-4\right)\left(x+1\right)$
$\frac{y^{-4}}{y^{-1}}$
$2\sin2x=\sin x$
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