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Solving: sin⁡(x)(1+cos⁡(x))1−cos⁡(x)\frac{\sin\left(x\right)\left(1+\cos\left(x\right)\right)}{1-\cos\left(x\right)}
Solve instead: sin(1+cos)1−cos(1+cos)\frac{sin\left(1+cos\right)}{1-cos\left(1+cos\right)}
f(x)=(sin(x)(1+cos(x)))/(1-cos(x))−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

sin(1+cos)1−cos(1+cos)\frac{sin\left(1+cos\right)}{1-cos\left(1+cos\right)}

Step-by-step Solution

1

Multiply the single term sin⁡(x)\sin\left(x\right) by each term of the polynomial (1+cos⁡(x))\left(1+\cos\left(x\right)\right)

sin⁡(x)+cos⁡(x)sin⁡(x)1−cos⁡(x)\frac{\sin\left(x\right)+\cos\left(x\right)\sin\left(x\right)}{1-\cos\left(x\right)}

Final answer to the exercise

sin⁡(x)+cos⁡(x)sin⁡(x)1−cos⁡(x)\frac{\sin\left(x\right)+\cos\left(x\right)\sin\left(x\right)}{1-\cos\left(x\right)}

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sin(1+cos)1−cos(1+cos) 
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