$$\left(\sin^2\left(x\right)\cos\left(y\right)\right)+\left(\cos^2\left(x\right)\cos\left(y\right)\right)=\cos\left(y\right)$$

$$\frac{\left(3+4\right)}{7}$$

$$ac+bc+2ax\:2bx$$

$$\frac{dy}{dx}=-yx$$

$$\frac{d}{dx}\left(3csc\left(x\right)+6cos\left(x\right)\right)$$

$$\int\left(x\sqrt{16-x}\right)dx$$

$$9-m^2$$