$-2\left(-12\right)\left(-3\right)$
$\int\left(\frac{16}{1+cos\left(4x\right)}\right)dx$
$\frac{6x^4-2x^3+2x-5}{x-2}$
$x^2-2x+6x-12$
$\int\:\frac{2x}{\left(x^2+x+1\right)}dx$
$-1\cdot2\cdot3$
$\left(y-\frac{41}{12}\right)^2$
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