$\frac{z^8-1}{z+1}$
$\frac{d}{dx}\left(y=\left(1+\frac{1}{x}\right)^x\right)$
$\int x^5\left(7+x^2\right)^{\frac{1}{2}}dx$
$5x-7\le7x-1$
$a^2-6a^2+1$
$\frac{5^7}{5^{-7}}$
$\left(x+10\right)x\left(x+6\right)$
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