$-4x^2+4x+1$
$\sin\left(16\right)\cos\left(29\right)+\sin\left(29\right)\cos\left(16\right)$
$\left(-3\right)^6\cdot4^3\cdot\left(-3\right)^8$
$\int_0^y\left(x+y\right)^2dx$
$x^2+8x+10=3$
$y'=\frac{-y}{x}$
$\int-tan\left(\frac{x}{2}\right)dx$
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