$\lim_{x\to\infty}\left|1+\frac{3}{x}\right|^x$
$\int\left(24x\:-\:14\right)\left(6x^{2\:}-7x+6\right)^4dx$
$-\frac{5}{\frac{1}{4}}$
$\left(a^2-6\right)\left(a^2+11\right)$
$16+5-26+3-6-14$
$4c^4-12c^7+9c^{10}$
$x^2-8x+0$
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