$5\cdot3-\left(-3\right)^3$
$\left(y_{2}-3.6\right)\left(y_{2}+4.7\right)$
$4-\left(5\right)\cdot\left(-3\right)$
$\frac{891.7993}{23.74}$
$6x^2+11x-2=0$
$3x-4y=8$
$5x^{11}\right)^{2}$
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