$\lim_{x\to-3.5}\frac{\tan\left(x+4\right)}{x+4}$
$1-\left(-6\right)-\left(-2\right)$
$\left(\:m+8\right)\left(m-10\right)$
$2x+4=x+1$
$\left(0.3a+0.5b\right)^2$
$4\cdot\pi\cdot2^3$
$7\left(-3\right)-5\left(-2\right)+\left(-6\right)\left(-4\right)$
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