$\frac{4x^2}{2x^3}$
$\left(3a^2+4ab+4b^2\right)\left(2a+3b\right)$
$y'=\frac{3x^2+4x-4}{\:2y-4};\:\:y\left(1\right)=3$
$\int_{x^3}^{x^2}\frac{1}{x^2}dx$
$p^2-p+2$
$\sqrt{b^2}^2$
$8b+6-6$
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