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Solving: dydxsin⁡(y)+ysin⁡(x)=0\frac{dy}{dx}\sin\left(y\right)+y\sin\left(x\right)=0
Solve instead: dydxx sin(y) + y sin(x)\frac{dy}{dx}x\:sin\left(y\right)\:+\:y\:sin\left(x\right)

Exercise

dydxx sin(y) + y sin(x)\frac{dy}{dx}x\:sin\left(y\right)\:+\:y\:sin\left(x\right)

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Final answer to the exercise

∑n=0∞(−1)ny(2n+1)(2n+1)(2n+1)!=cos⁡(x)+C0\sum_{n=0}^{\infty } \frac{{\left(-1\right)}^ny^{\left(2n+1\right)}}{\left(2n+1\right)\left(2n+1\right)!}=\cos\left(x\right)+C_0

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dydx x sin(y) + y sin(x)
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