$\int\left(6x+6\right)^3\left(6\right)dx$
$\frac{d}{dx}b^x$
$\frac{9+16\left(1.8956\right)^4}{1.8956^2}$
$\frac{\left(x^2-x+3\right)}{x-2}$
$\sqrt[2]{-4}$
$-3\cdot26.-5$
$\int\left(10xcos\left(5x^2-1\right)\right)dx$
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