$\int\frac{x^2}{e^{x^3}}\:dx$
$\frac{x^2+x+1}{x+1}$
$\left(1+x^6\right)\frac{dy}{dx}=\frac{x^5}{y}$
$\lim_{x\to0}\left(6\right)$
$-8\:restar\:5$
$e^{-2y}dy=\frac{1}{3}e^{3x}dx$
$x^2+x+3\le\:9$
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