$y'=\frac{\left(1-y\right)^3}{2}$
$\lim\:_{x\to\:-3}\left(\frac{6x^2+6x-36}{x+3}\right)$
$2x^2\left(2x^2+2x-4\right)$
$\lim_{x\to8}\left(10\right)$
$-2m^3n^2-15m^3n^2\:$
$\lim\:_{x\to\:\:1}\left(\frac{\sqrt{x+8}+3}{x-1}\right)$
$-2x+8=18$
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