$\int\frac{1.}{x\sqrt{x^2+4}}dx$
$\int_0^1\left(\frac{2x-5}{x^2-5x+6}\right)dx$
$4x-10x+7x-3x$
$\left(3-4x\right)^5$
$\frac{\tan^2\left(x\right)}{\left(\sec\left(x\right)+1\right)^2}$
$x\cdot\frac{dy}{dx}+y$
$-x+11=x+1$
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