$\frac{a^{12}+250^{12}}{a^6-125^6}$
$4x^2+8x+1=5$
$\sqrt[3]{z}-5=2$
$x^4-8x^3$
$\left(8x^3-27\right)$
$\frac{\left(-10\right).\left(-5\right)}{\left(-2\right)}$
$45+65+78+98+12+32+25$
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