$cosx+senx=0$
$\sqrt{5x^2}\sqrt{40x}$
$x+y-z=-3$
$\lim_{x\to2}\left(\frac{x^4-4x^4+4y^2}{x-2}\right)$
$\lim_{h\to0}\left(\frac{\left(3+h\right)^{-1}-3^{-1}}{h}\right)$
$\sqrt[4]{b^7}m^3$
$\int\frac{1}{x^2}+\frac{4}{x\sqrt{x}}+2\:dx$
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