$\frac{\left(2x+13\right)^5}{\left(5x^2-12x+5\right)}$
$\lim_{x\to0}\left(-\frac{1}{t}e^{\frac{1}{t}}\right)$
$\left(2x\right)\cdot9-\left(3x^2\right)+5xy$
$x^2-y^2=9$
$4x-\frac{3}{5}>-x-6$
$\frac { 9 a ^ { 5 } } { 2 a ^ { 3 } }$
$x^2-12x+36=49$
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