∫(sin2x+cos2x)2dx\int\left(\sin2x+\cos2x\right)^2dx∫(sin2x+cos2x)2dx
4x2y−3y+1=x34x^2y-3y+1=x^34x2y−3y+1=x3
y′=3x2yy'=\frac{3x}{2y}y′=2y3x
∫1(x+1)(x2+16)dx\int\frac{1}{\left(x+1\right)\left(x^2+16\right)}dx∫(x+1)(x2+16)1dx
15−2⋅3−515-2\cdot3-515−2⋅3−5
x5+3x4x2+x−6\frac{x^5+3x^4}{x^2+x-6}x2+x−6x5+3x4
(15c−45)(15c+45)\left(15c-45\right)\left(15c+45\right)(15c−45)(15c+45)
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