$\left(4x+2\left(-1+3x-2x^2\right)\right)$
$f\left(x\right)=\left(4x^3+1\right)^2$
$\frac{d}{dx}\frac{x-3}{2}$
$yx'=ye^y-2x$
$\left(\frac{1}{5}x^3-\frac{1}{3}\right)^2$
$3\left(x-5\right)-5>5\left(x+1\right)-1$
$\frac{3}{5}^{-4}$
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