$\sqrt[0.5]{3}$
$\frac{25a^3b^2c+10a^2bc^3}{5a^4b^2c}$
$16+8\left(x+y\right)+\left(x+y\right)$
$+14+14\left(-14\right)$
$\frac{2}{3}\left(2\left(2\right)+2\right)+\left(-5\right)$
$\frac{d^2}{dx^2}\left(x^2+\frac{x^6}{3}+\frac{1}{20}\right)$
$0,5+0,33333333333333333$
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