x+3x2−7x+12\frac{x+3}{x^2-7x+12}x2−7x+12x+3
312⋅2233\frac{1}{2}\cdot2\frac{2}{3}321⋅232
limx→11−cos(4x)xsin(5x)\lim_{x\to1}\frac{1-\cos\left(4x\right)}{x\sin\left(5x\right)}x→1limxsin(5x)1−cos(4x)
limx→∞(2x3−2x2+72x2+7x+1)\lim_{x\to\infty}\left(\frac{2x^3-2x^2+7}{2x^2+7x+1}\right)x→∞lim(2x2+7x+12x3−2x2+7)
−(x+3)3-\left(x+3\right)^3−(x+3)3
(4x2+12y5)2\left(4x^2+\frac{1}{2}y^5\right)^2(4x2+21y5)2
−6+4−3−2−8+5-6+4-3-2-8+5−6+4−3−2−8+5
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