$\frac{z^2}{\left(2-z\right)}$
$7x+6x-x$
$\cos\left(x\right)\cot\left(x\right)=4\sin\left(x\right)-4$
$2x^2-3x+9=0$
$6+\left(-2\right)-3-\left(-4\right)$
$\left(4z^3w\right)^2$
$\left(2\right)\cdot\left(-8\right)$
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