$\lim_{x\to0}\left(\frac{sinx}{4x}\right)^{\frac{1}{x}}$
$2x^2-y^4+2=0$
$\frac{x^3+3x^2+3x+1}{x}$
$\int7\sin^2\left(2x\right)dx$
$-\left(x^2-4x-4\right)$
$\frac{\left(-9sin\left(t\right)\right)}{9sec\left(t\right)}$
$\lim_{x\to-2}\left(\frac{3}{x+2}\right)$
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