$y=\left(-2x^2-x\right)\frac{1}{x}$
$12x^2+x+1=0$
$\left(y^2-3x\right)\left(y^2+3\right)$
$-\frac{585}{45}$
$\log\left(16+2b\right)=\log\left(b^2-4b\right)$
$-147xym^2=-147x^3y^2m^2$
$\lim_{x\to0}\left(1-\frac{1}{2}x\right)^{\frac{4}{x}}$
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