$\frac{2x^2}{2x^2-4x+3}$
$4t\left(1-t\right)^3$
$\frac{d^2y}{dx^2}=-3$
$y=e^{x^2-3x}$
$\frac{cos\left(2x\right)+sin\left(2x\right)-1}{cos\left(2x\right)-sin\left(2x\right)+1}=tan\left(x\right)$
$\int\frac{\left(y^4-9\right)}{y^3+2y^2}dy$
$4pg^0$
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