$y=\frac{x^3}{3\left(x+2\right)}+\frac{x^2}{x+2}+c$
$2cos\left(\theta\:\right)cos\left(2\theta\:\right)-3cos\left(2\theta\:\right)=0$
$\frac{6x^2-2x-1}{4x^3-x}$
$\frac{27x^3+8}{3x-2}$
$\sqrt{9ab}.\sqrt{12ab^3}$
$33.33^2$
$5a+2b=10$
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