$\frac{2^3x^3y^4}{2xy^2z}$
$3-x<-4$
$\left(x^2+3x+1\right)\left(x^2-2\right)$
$3\left(v+6\right)-v\left(6-3v\right)$
$\left(\frac{1}{3}xy-z^6\right)\left(\frac{1}{3}xz+z^6\right)$
$\frac{\left(20\right)}{\left(4\right)^5}^6$
$\left(x+3\right)-\left(3x+1\right)$
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