2x+1−5≥0\frac{2}{x+1}-5\ge0x+12−5≥0
(5x4+4x3−7)−(2x2)\left(5x^4+4x^3-7\right)-\left(2x^2\right)(5x4+4x3−7)−(2x2)
−3u−7≤2u+8-3u-7\le2u+8−3u−7≤2u+8
874−5792874-5792874−5792
2+6c+5c+92+6c+5c+92+6c+5c+9
4x + y = 8 4x\:+\:y\:=\:8\:4x+y=8
∫(x3x2+43)dx\int\left(x^3\sqrt{x^2+43}\right)dx∫(x3x2+43)dx
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