$\left(b^{x+1}\right)^2$
$x\left(a+5\right)-3\left(a+5\right)$
$i^2\:y\:-xy\:_{-8}\:cuando\:i=-\:e\:y\:=-2$
$12+\left|\left(-18\right)+\left(-100\right)\right|-130$
$-1\:=\:4\cos^2x\:-\:2$
$\frac{6^{-3}}{6^{-4}}$
$2x+9>3x$
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