$b^2+6b=16$

$5y^2-13y-6$

$\int_1^{\infty\:}\:\frac{8x}{\left(x+1\right)^3}dx$

$\lim_{x\to\infty}\left(\frac{\tan\left(x\right)}{3x}\right)$

$\sqrt{x^2}-1$

$\left(6m^2-3mn-7n^2\right)\left(m^2-5mn+n^2\right)$

$\lim_{x\to\frac{\pi}{2}}\left(\frac{\sin\left(4x\right)}{x}\right)$