(4+v)(16−4v+v2)\left(4+v\right)\left(16-4v+v^2\right)(4+v)(16−4v+v2)
5x−725x^{-\frac{7}{2}}5x−27
sin2−cos21−sin2=tan2\frac{\sin^2-\cos^2}{1-\sin^2}=\tan^21−sin2sin2−cos2=tan2
f (x) = (x +4)5f\:\left(x\right)\:=\:\left(x\:+4\right)^5f(x)=(x+4)5
5−2x≤3+2⋅(4−2x)5-2x\le3+2\cdot\left(4-2x\right)5−2x≤3+2⋅(4−2x)
−6x − 10x −55 =137-6x\:-\:10x\:-55\:=137−6x−10x−55=137
limx→0(tanx−1)⋅sec2x\lim_{x\to0}\left(\tan x-1\right)\cdot\sec2xx→0lim(tanx−1)⋅sec2x
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